(b+2)(b+4)=b^2+4b+4

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Solution for (b+2)(b+4)=b^2+4b+4 equation: 



(b+2)(b+4)=b^2+4b+4

We move all terms to the left:

(b+2)(b+4)-(b^2+4b+4)=0

We get rid of parentheses

-b^2+(b+2)(b+4)-4b-4=0

We multiply parentheses ..

-b^2+(+b^2+4b+2b+8)-4b-4=0

We add all the numbers together, and all the variables

-1b^2+(+b^2+4b+2b+8)-4b-4=0

We get rid of parentheses

-1b^2+b^2+4b+2b-4b+8-4=0

We add all the numbers together, and all the variables

2b+4=0

We move all terms containing b to the left, all other terms to the right

2b=-4

b=-4/2

b=-2

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